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JazzyD

Active Member
Toronto, New Jersey and Golden State all have the same record at the end of the season? How does the league decide the draft order?
 
If two teams are tied they flip a coin. If it's three teams, they must use some other equal-chance method.

However, Toronto and New Jersey play each other the last night of the season, so they certainly won't be tied at 22 wins. That's why the Jazz need GS to win one more so they can keep up with the winner of the NJ @ Tor game and then hope for the best in the coin flip and lottery.
 
Toronto, New Jersey and Golden State all have the same record at the end of the season? How does the league decide the draft order?

I believe that David Stern shows up and says, "Pick a number between 1 and 10". In the extremely unlikely event that they all end up equal distances away from the number then they move on to rock, paper, scissors.
 
If two teams are tied they flip a coin. If it's three teams, they must use some other equal-chance method.

However, Toronto and New Jersey play each other the last night of the season, so they certainly won't be tied at 22 wins. That's why the Jazz need GS to win one more so they can keep up with the winner of the NJ @ Tor game and then hope for the best in the coin flip and lottery.

Our best hope is tues the 24 against Nola for a gsw win although I think minny Tonight is a winnable game.
 
While it's true tiebreakers are broken pre-lottery - ultimately they make only a marginal difference as the number of draft combinations are split as equally as possible between the two teams. The coin flip is used to determine which team ends up with 1 extra combination of lottery balls.

For example, if the 2nd & 3rd worst teams record-wise finish with identical records - they split the total number of ping-pong balls allotted to the 2nd & 3rd worst-teams (199 & 156 combinations respectively) - and the tie breaker is used to determine which team ends up with a single extra ping-pong ball (178 vs 177).

...so if GS and NJ/Tor are tied - they'll split the number of chances and if it's an odd number the tie breaker would be used to settle the difference.
 
Vslice speaks the truth. And wasn't it last year we were all watching as NJ finished with the same record as Sacramento and Sacto won the coin toss for the one extra chance?
 
the case where the difference is not marginal

While it's true tiebreakers are broken pre-lottery - ultimately they make only a marginal difference as the number of draft combinations are split as equally as possible between the two teams. The coin flip is used to determine which team ends up with 1 extra combination of lottery balls..


The tie breaker becomes critical if neither team gets a top 3 pick. So if GS & & NJ finish 7/8, NJ wins the flip, neither gets a top 3 pick, then the Jazz get the 8th pick. If GS wins the flip, the Jazz do not get the 2012 GS pick.
 
The tie breaker becomes critical if neither team gets a top 3 pick. So if GS & & NJ finish 7/8, NJ wins the flip, neither gets a top 3 pick, then the Jazz get the 8th pick. If GS wins the flip, the Jazz do not get the 2012 GS pick.
Agreed, I was thinking in terms of winning the lottery but you're correct - it would impact the Jazz if GS finishes in a tie for 7th.
 
Toronto, New Jersey and Golden State all have the same record at the end of the season? How does the league decide the draft order?

Stern will take all 3 owners back into a secluded room to play Russian Roulette. The winner gets the best pick. The losers not only lose their lives but their franchises will face contraction.
 
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