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Marc Stein: Jazz-Warriors discuss pre-Lottery trade (Source says trade "likely")

Outside of the Jazz getting #8, the only other thing I want to see is Brooklyn get a top three pick so Portland doesn't get their pick for the Gerald Wallace heist.
 
Seems like all the trades that get the most press never seem to happen and the trades that you hear nothing about are the ones that actually go through.
 
Weezur said:
Everybody flip 2 coins and see if u get 2 heads or 2 tails. (call it first)....
That is roughly the chance we have now
Click to expand...

regardless of how many coins are flipped, the chances are always 50%. Each coin flip counts as a separate instance and has no effect on the previous (or next) coin flip.

A better thing to try would be to find one of these: https://en.wikipedia.org/wiki/4-sided_die (call a number) and if you get that number, that's the chances we have at getting our pick.

--note: since I'm a D&D nerd and happen to have one of these at my desk at work, I tried it. Called a 2, got a 3. Tried it again, called a 4, got a 4! *We're totally getting that pick!*
 
If the Jazz really want to get rid of Jefferson or Raja, and they can't get any assets in return, they can just amnesty or waive them. They both expire in a year, so there's absolutely no reason why the Jazz should have to add a top 10 pick to move either of them. That would be ****ing retarded (nevermind that Jefferson almost certainly has positive value to some teams in the league).
 
chawx said:
regardless of how many coins are flipped, the chances are always 50%. Each coin flip counts as a separate instance and has no effect on the previous (or next) coin flip.
Click to expand...
Uh...I think you've misinterpreted what he said. The chance of flipping consecutive tails is 25%. That is, you can flip heads-heads, heads-tails, tails-heads or tails-tails all with equal probability (25%...although the middle two events can be considered a 50% chance of flipping one of each).
 
chawx said:
regardless of how many coins are flipped, the chances are always 50%. Each coin flip counts as a separate instance and has no effect on the previous (or next) coin flip.

A better thing to try would be to find one of these: https://en.wikipedia.org/wiki/4-sided_die (call a number) and if you get that number, that's the chances we have at getting our pick.

--note: since I'm a D&D nerd and happen to have one of these at my desk at work, I tried it. Called a 2, got a 3. Tried it again, called a 4, got a 4! *We're totally getting that pick!*
Click to expand...

No,
The chances of 2 heads in 2 flips = 25%.
The chance getting 2 tails in 2 flips = 25%
The chance of getting heads + tails = 25%
And the chance of getting tails + heads = 25%. Adds up to 100%.

You're right that each flip is an independant trial of 50% probability.
 
Weezur said:
No,
The chances of 2 heads in 2 flips = 25%.
The chance getting 2 tails in 2 flips = 25%
The chance of getting heads + tails = 25%
And the chance of getting tails + heads = 25%. Adds up to 100%.

You're right that each flip is an independant trial of 50% probability.
Click to expand...

I got ya...for it to be a true 25% chance though, you would need to call upfront what you think the coin will do twice in a row and get it correct to "win". Basically, call heads, and flip it twice...if you get 2 heads, you're a "winner"!
 
chawx said:
I got ya...for it to be a true 25% chance though, you would need to call upfront what you think the coin will do twice in a row and get it correct to "win". Basically, call heads, and flip it twice...if you get 2 heads, you're a "winner"!
Click to expand...

Yep. Or flip 2 coins simultaneously and call it.

There wouldn't happen to be a D&D dice that you could get 27% with, is there? :P They've got some pretty crazy D & D dices that I remember.
Maybe a 100 faced die? Or.....a 9% die could work too if you do it right.

EDIT: 9% wont work, that was dumb, dunno where I got that.
 
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